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Add Day 18 part 1 solution using line crossing
author IBBoard <dev@ibboard.co.uk>
date Tue, 02 Jan 2024 16:04:33 +0000
parents ad73a2ff3d06
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--- Day 15: Lens Library ---

Implement a custom hashing algorithm:
    Determine the ASCII code for the current character of the string.
    Increase the current value by the ASCII code you just determined.
    Set the current value to itself multiplied by 17.
    Set the current value to the remainder of dividing itself by 256.

Values are comma-separated. For example:

rn=1,cm-,qp=3,cm=2,qp-,pc=4,ot=9,ab=5,pc-,pc=6,ot=7

Gives 11 individual steps; the result of running the HASH algorithm on each of the steps is as follows:

    rn=1 becomes 30.
    cm- becomes 253.
    qp=3 becomes 97.
    cm=2 becomes 47.
    qp- becomes 14.
    pc=4 becomes 180.
    ot=9 becomes 9.
    ab=5 becomes 197.
    pc- becomes 48.
    pc=6 becomes 214.
    ot=7 becomes 231.

Then sum the hashes.